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🔥 Top post: Complex Grassmannians in the wild There is a fun approach to wir · 3 likes + reposts
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Moishe Kohan on Jacobian conjecture. Math Stackexchange, 2017
https://minily.org/5m1YwldYxH
- Another way to get big codebooks admitting easy decoding is considering finite group orbits. WIP. Related concepts: fundamental domain, Clifford-Klein form and other fun stuff. One thing on my todo list is to try to look into arithmetic …
Cool. So you pick your codebook based on maximal minimum pairwise distance criterion?
- That's how it was traditionally done. Kind of like the sphere packing problem. But it turns out that a better cost function is given by determinants. N…
Hang on! Nearest neighbor? With what kind of distance?
- Turns out that if we represent with matrices whose rows are ON basis of the subspaces, then the maximum likelihood detector is equivalent to the nearest neighbor in the so called cho…
So instead of encoding our data into vectors we can encode them as points on the Grassmannian and we don't have to know \( H \) at all!
How do we decode?
- We fix a finite set of points as our codebook, assume that \(H\) is iid Gaussian (s…
So at time slot \(i\) we send vector \(x_i\) and receive vector \(y_i\) with so that \( y_i = x_i H + z_i\).
We can stack these vectors together and write these \(T\) equations as one matrix equation
\[Y = XH + Z\]
where \(X\) has \(x_i\)…
So that's fine for, say, \(M = N = 2\) but terrible for \( M = N = 32\). Moreover, this matrix enters the decoding algorithms and there every bit of latency matters.
Is there other way to do this?
The answer is so called "block fading" whi…
Turns out that adding more antennas has nice benefits that have to do with the fact that the high dimensional normal random vectors tend to concentrate on the sphere. But there is a problem!
The receiving party has to decode \(x\) from \( …
The simplest function is linear \( y = Hx \) but we have to account for some (white additive Gaussian) noise. Hence our basic relationship between transmitted signal and received signal is
𝑦=𝐻𝑥+𝑍
where \( Z\) is iid complex Gaussian ra…
You have \( M \) antennas at the transmitting side and \( N \) antennas at the receiving side.
The \(i\)th transmitting antenna sends an EM wave \( x_i \) and the receiving party gets \( y_j \) on its \(j\)th antenna. Since the EM wave c…
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